Best way to parse lines in standard C++?

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Program output can't be licensed GPL unless the output contains some of the program's code.

[edit]
fsf wrote:
/* As a special exception, when this file is copied by Bison into a
Bison output file, you may use that output file without restriction.
This special exception was added by the Free Software Foundation
in version 1.24 of Bison. */
Last edited on
That's a relief. Thanks. I was somewhat confused by this statement:

Bisonc++ may be used according to the GNU General Public License (GPL). In short, this implies that everybody is allowed to use b() and its generated software in any program he/she is developing.


http://bisoncpp.sourceforge.net/bisonc++02.html#l2

-- I thought that meant that generated code was under GPL.
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