What's your output?

[LB]

Run this code and tell what your output is.

#include <iostream>
using namespace std;

void PrintOrder(unsigned long a, unsigned long b, unsigned long c, unsigned long d)
{
	cout << a << b << c << d << endl;
}

unsigned long Staticount()
{
	static unsigned long v = 0;
	return(v++);
}

int main()
{
	PrintOrder(Staticount(), Staticount(), Staticount(), Staticount());
	cin.sync();
	cin.ignore();
}

My output is 3210, my compiler in VC++2008 Express evaluates the parameters from right to left, which was the opposite of what I thought. I'm curious as to the order your compiler(s) evaluate(s) parameters, as the order is undefined. This tricked me up once, because I assumed the parameters to a function call would be evaluated from left to right, I spent hours debugging this until someone finally pointed it out to me >_<

[Disch]

I also get 3210 on VC++2010 express, but as you mentioned, the output is undefined.

[S6k9GNh0]

If I'm not mistaken, it's naturally read from right to left because of the nature of the underlying assembly. I'm not to avid in how Assembly works (well, I understand ASM, but not the concepts that surround it) so I really can't be certain about it.

[helios]

A teacher once told me it's done this way to implement variadic functions. If the parameters are pushed right to left, the stack will look like this:
<variadic parameters>
3rd parameter
2nd parameter
1st parameter
Then, by passing a pointer to the third parameter and since the beginning of the stack frame is always known, it's easy to determine how many parameters were passed.

[S6k9GNh0]

^ this. This is what I was talking about.