Solve for i

[Seraphimsan]

no really, I think you'll like it.

9x - 7i > 3(3x - 7u)

[Albatross]

Aw. So cute...

-Albatross

[xander333]

Are we supposed to single out i?

[Albatross]

I believe so. It makes sense if you do.

-Albatross

[D80DSL3A]

i < 3u ??? Thought it might lead to the egotistical statement i > u but it doesn't.

[Zhuge]

The < 3 is a heart, I would think.

[Seraphimsan]

Zhuge is right. I found this scribbled in my ex girlfriends hand writing in an old note book from highschool. I thought it was cute so I posted it here :3

[wolfgang]

01001001 00100000 00111100 00110011 00100000 01010101 00100000 00110010

[D80DSL3A]

Ohhh.. i <3 u. very cute. Perhaps if I weren't being cynical I would have seen that.

[chrisname]

i <3 u 2!

9x - 7i > 3(3x - 7u)
9x - 7i > 9x - 21u
-7i > -21u
7i < 21u
i < 3u

[ultifinitus]

in other words, our love is complicated =)

[wolfgang]

If it wasn't for the unknown 'u', 'i' would be easy to solve. :P

[chrisname]

Yes it would. The only thing that's difficult about that equation (for me) is remembering to flip the more-than sign when you make i and u positive.

I re-arranged it to put u and i together:

i < 3u
i/u < 3
u/i < 1/3

[Seraphimsan]

yea but now our love is < .3333333333333~

[Kyon]

Not really, since u and i are divided, how can we love each other?

[ne555]

when you invert a fraction the relation inverts too
i < 3u
i/u < 3 (only if u>0)
u/i > 1/3
I think the problem is to find 'u'.

off-topic: 2! == 2!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

[chrisname]

Obviously, since 2! is 2...

[Browni3141]

It's cool, but I'd use an uppercase I to avoid confusion with the imaginary number i.

[ne555]

I meant sqrt(-1/9) < pow(u, factorial(factorial(factorial(2))))

[thomas430]

lol @Browni3141