Data analysis, Probability, Statistics, ad Discrete Math
1)Mary has 6 red marbles and 3 blue marbles in a jar picking randomly.
A)She picks 2 marbles from the jar one at a time, If both marbles that she picks must be red in order to win, would picking with replacement or without replacement give her the higher probability of winning?
B)She picks two marbles of the same color. Would the probability of picking with replacement of without replacement give her the higher probability of winning?
C)She picks 2 marbles. In order to win, she must select one marble of each color on the first pick and another color on the second pick. Would picking with replacement or without replacement give her a higher probability?
This is all straight-up, simple probabilities, a la secondary school.
A) You'll need to figure the probability of picking a second red with replacement and then the probability without replacement. Which is more likely to get you a second red? (Frankly, you don't really even need to know the exact probability -- just think about it a moment.)
B) This is the same as A, except that you now have two winning possibilities: 2 red or 2 blue. You've already calculated the probabilities of winning with reds. Now calculate the probabilities of winning with blues.
C) Ad nauseum. You must now win by choosing two marbles of different colors. Which gives you the better chances of choosing a different color: with or without replacement?
Remember, the probability of something happening is the number of desired outcomes over the total number of possible outcomes. So the probability of choosing a red marble from your bag is 6/(6+3), or 2/3. The probability of choosing a blue marble is then 1/3.
Remember also that when you want to chain probabilities, you multiply the individual probabilities together.