How to have the console recognize every word?

[ccrowley96]

#include "stdafx.h"
#include <iostream>
#include <string>
using namespace std;

int x;
string favword;

int main()
{
cout << "Enter your favorite number (between 1 and 10 ... don't mess around ima computer.... I'll know" <<endl;

do
{
cin >> x ;
if (x < 1)
{
cout << "Not cool" <<endl;
}

else if (x > 10)
{
cout << "Man I can't count that high" <<endl;

}
else if (x = string)
{
cout << "SYSTEM ERROR"<<endl;
exit(0);
}

}while(x < 1 || x > 10);



cout << "Well done" <<endl;
cout << "Now enter you favorite word" <<endl;
cin >> favword;
cout <<"[/code]this is your favorite word " << favword <<endl;
system("pause");
return 0;
}




I wan't this program to be able to recognize if a user types in any word ex. (apple, tree, house etc..) and print "system error" if a word is recognized not to be a number. The bold section of code is my failed attempt to try this. Basically I need to know what to make

(x = ?(every word)) in order to finish my console program. thanks for the help

[Disch]

Chervil already answered this question in your other post here:

http://cplusplus.com/forum/beginner/98128/