Printing from a vector of structs

[crimsonzero2]

Hello, I'm trying to print values from a vector of a struct and I don't really know how to do that. Here is a simple code that I have for now to test how to add data to the vector then attempt to print it out.

#include <iostream>
#include <vector>
#include <string>
#include <deque>
#include <fstream>

using namespace std;

struct Employee							//employee data
{
	int ID;
	string fname;
	string lname;
	double salary;
	int hpw;
	string work;
	int flag;
};
struct Employee a;
vector<Employee> AddEmployee;			//for adding employees
deque<Employee> ListEmployee;			//for listing in a sort() function later on

void Addemployee()
{
	
}

int main()
{
	
	a.ID = 1;
	a.fname = "A";
	a.lname = "A";
	a.salary = 20;
	a.hpw = 40;
	a.work = "m";
	a.flag = 1;
	AddEmployee.push_back(a);
	cout << AddEmployee.ID << endl;

	return 0;
}

Any help would be appreciated.

[vlad from moscow]

The compiler shall issue an error for this statement

cout << AddEmployee.ID << endl;

AddEmployee is an object of type std::vector<Employee>. The record AddEmployee.ID means that you are trying to call method ID declared in class std::vector. However class std::vector has no such a method. So before accessing ID you should get an object of type Employee where this data member is declared. The simplest way is to use the subscripting operator of class std::vector

cout << AddEmployee[0].ID << endl;


AddEmployee[0] returns an object of type Employee that has data member ID.

[vlad from moscow]

If you do not want to bother how many elements are contained in the vector and display all its alement you can use the range-based for statement

for ( const Employee &e : AddEmployee )
{
   std::cout << e.ID << std::endl;
}