Trying to output a letter with *?

I'm working on a project where I'm supposed to take in a letter like "A" and output this instead:

0***0
*000*
*****
*000*
*000*

using a grid

for now I'm trying to do that to the letter "A"


#include <iostream>
using std::cout;
using std::endl;

#include "Header.h"

void main()
{


int getA[5][5]= {{0,1,1,1,0},
{1,0,0,0,1},
{1,1,1,1,1},
{1,0,0,0,1},
{1,0,0,0,1}};



char c = '*';

replaceCharacters(getA);
}

void replaceCharacters(int data[5][5])

{

for (int i = 0; i <5; i++)
{
for (int j = 0; j < 5; j++)
{
if (data[i][j] == 1)
{
cout <<"*"<<endl;
}
else
{
cout << "0" << endl;
}

cout << endl;

}
}
}



My problem is that it outputs each and every cell of the grid on a new line.
So now it looks like this:

0
*
*
*
0

*
0
0
0
*

*
*
*
*
*
etc ...


do you know how to format it so that there's a new line after every 5th column?
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#include <iostream>
#include <stdlib.h>
#include <stdio.h>
using std::cout;
using std::endl;


void replaceCharacters(int data[5][5])

{
    for (int i = 0; i <5; i++)
    {
        for (int j = 0; j < 5; j++)
        {
            if (data[i][j] == 1)
            {
                cout <<"*";
            }
            else
            {
                cout << "0";
            }
            
        }
        cout << endl;
    }
}


int main()
{


int getA[5][5]= {{0,1,1,1,0},
{1,0,0,0,1},
{1,1,1,1,1},
{1,0,0,0,1},
{1,0,0,0,1}};



char c = '*';

replaceCharacters(getA);
return 0;
}
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