default parameters in constructor?

[gen1mx6]

this code won't compile. it gives a linking error because i'm calling a function that doesn't exist but i thought with the default parameters i should be able to instead of creating a new function that does this:

point()
{
x=0;
y=0;
}

i've tried ano parameter constructor calling this(0,0) and that doesnt work either have to much java on the brain.

#include <iostream>
using namespace std;

struct point{
	friend ostream& operator<<(ostream& out, const point &in);
public:
	point (int inputOne=0, int inputTwo=0)
	{
		x=inputOne;
		y=inputTwo;
	}
private:
	int x;
	int y;
};

int main()
{
	point pointOne();
	cout<<pointOne;
	return 0;
}

ostream& operator<<(ostream& out,const point &in)
	{
		out<<"x="<<in.x<<" "<<"y="<<in.y;
		return out;
	}

[gen1mx6]

well, i've found out the problem. its because of

point pointOne();///doesn't compile
point pointOne;/// will compile 

but why is there a difference?

[jsmith]

Google "C++ most vexing parse"

The first line looks to the compiler like you a prototyping a function named "pointOne" which takes no parameters and returns a point.

[gen1mx6]

thanks for the info