How Can I Add '\0' in char *msg = "Hello World"?

[f ben isaac]

char *here = "hello there whats up";
//&here[20] = '\0'; this does not work! 20 is the position after p
cout<<here<<" ****"<<endl;
cout<<&here[5]<<" **test**"<<endl;

1. How can i add a char '\0' after the letter p?
2. How can i add a termination char '\0' in the middle of the string?

This a sample example. Don't worry about the for loop, etc.

This is C++

[writetonsharma]

not possible, *here is a constant pointer and you cant change it.
it will fault.

if you want to do it, then explicitly allocate memory to it using malloc and then change the value.

[guestgulkan]

Why would you want to add '\0' after the last character?
It already has a '\0' after the last character.

PS.. The pointer isn't constant, it is the object (in this case the text string literal) that is constant (which is why you can't modify it).

[f ben isaac]

>>Why would you want to add '\0' after the last character?

I mainly asked to know how to place \0 in a middle a string. I think i have to use memmov()

>>The pointer isn't constant,

Right, its not constant...

>>it is the object (in this case the text string literal) that is constant (which is why you can't modify it).

1. Is string in C++ immutable?
2. I would agree with this statement that the text is object if the text stored in a variable declared as string, not char * since char does not have member functions you can call such as .size(), etc. Can you clarify your statement more please.

[Bazzy]

try with

char here[] = "hello there whats up";
here[11] = 0;

Here 'here' is an array so you can do whatever you want to its elements

[f ben isaac]

Yea, i know how to do that, but i'm ought to use the mentioned example. I got it anyway. Thansk

[writetonsharma]

when you declare and initialize the pointer same time the string is constant and hence you cant change the value. so this way you can take a pointe. either you have to take string as Bazzy said or else you have to allocate memory using malloc.