c: structs func and pointers

[quant]

hi all,
I've a truble with slimilar of this code..

struct first *fir;
struct second *sec;
func(struct firs *fi, struct s *se){
......
return func(fi,se); // return value from func which take pointer on struct firs  and s
}
errno=func(fir,sec); // take pointer on struct first  and second
//warning: passing argument 2 of 'func' from incompatible pointer type 

I wrote two equal methog structs usage, but second take it's warning. Why it's happened?

[helios]

In line 7, sec is a 'second *', but func() takes an 's *' as the second parameter.

By the way, 'first', 'second', 'firs', and 's'? Were those the most meaningless names you could come up with?

[quant]

In line 7, sec is a 'second *', but func() takes an 's *' as the second parameter.

hm, why myfunc take first parameter very well and broke on second?
I made something this
errno=func(fir,(struct second*)&sec);
and this
errno=func(fir,&sec);
but it's doesnt' work.

By the way, 'first', 'second', 'firs', and 's'? Were those the most meaningless names you could come up with?

I wrote just a simple like my code.

[jsmith]

Meaningless variable names are the antithesis to simplicity.

[quant]

why?
It's not essential with it.

struct numbers *seq;
struct data *buf;
int main(struct num *x, struct str *y){
......
return main(x,y);
}
errno=func(sec,buf);

How I can use function main which be able take second argument buf, are type of struct str?

[jsmith]

main() is a reserved symbol/"function" that can only take certain arguments, namely

int argc, char* argv[], char** arge

or

int argc, char* argv[]

or

no parameters

So you can't write line 3 above; you need to name the function differently.

Also, it is not allowed by the standard to call main() from within your program. Not all compilers adhere to that rule, however.

[quant]

yes, it's very well, but warning provoke when I tride use function in another function.

struct numbers *seq;
struct data *buf;
int my_func(struct num *x, struct str *y){
......
return my_func(x,y);
}
errno=my_func(sec,buf);

[jsmith]

Then you have a syntactic error in your code.

[quant]

my god, where? Warning is appeared when I call my_func here...
errno=my_func(sec,buf); //warning: passing argument 2 of 'my_func' from incompatible pointer type

[jsmith]

Well, the warning is fairly explicit.

my_func takes a pointer-to-something as its second parameter, but buf is a pointer-to-something-else.

[helios]

Curiously enough, that's exactly what I said in my first post.

[quant]

Curiously enough, that's exactly what I said in my first post.

In line 7, sec is a 'second *', but func() takes an 's *' as the second parameter.

helios, ok. Just I want to understood, which's method I gotta use there so as to replace that?

struct first *fir;
struct second *sec;
func(struct firs *fi, struct s se){ // if I do that, its not improve situation.
......
return func(fi,&se);
}
errno=func(fir,sec);// me need doing something with second argument here, but I don't know how.