converting a word to lowercase

[shotjase]

Can anyone help me finish this?

void lowerCase(char ch, string array[])
{
int index;

ch = tolower(ch);






}

[guruplus]

Hello,
Here is what u need;)

#include <iostream>
using namespace std;
char* toLowerCase(char* str)
{	
	int differ = 'A'-'a';
	char ch;
	int ii = strlen(str);
	for (int i=0; i <ii;i++)
	{
		strncpy(&ch,str+i,1);
		if (ch>='A' && ch<='Z')
		{
			ch = ch-differ;
			memcpy(str+i,&ch,1);
		}
	}
	return str;
}

 int main()
{
	char* pstr = (char*)calloc(100,sizeof(char));                                              
	string s;
	s="TestAAAAAAAAA";
	strcpy(pstr,"BBaaCCdRT");
	printf("%s\n",toLowerCase(pstr));
	strcpy(pstr,s.c_str());
	printf("%s\n",toLowerCase(pstr));
	getchar();
	return 1;
}

[guruplus]

If you want to use string as parametr,
this procedure helps you;)

string toLower(string strr)
{	
	char str[100];
	string ret;
	strcpy(str,strr.c_str());
	int differ = 'A'-'a';
	char ch;
	int ii = strlen(str);
	for (int i=0; i <ii;i++)                                                           
	{
		strncpy(&ch,str+i,1);
		if (ch>='A' && ch<='Z')
		{
			ch = ch-differ;
			memcpy(str+i,&ch,1);
		}
	}
	ret = str;
	return ret;
}

[z05DSL3A]

Here are two ways to convert a string:

#include <iostream>
#include <string>
#include <cctype>

#include <algorithm>

//
// The For loop way
void toLowerCase(std::string &str)
{
	const int length = str.length();
	for(int i=0; i < length; ++i)
	{
		str[i] = std::tolower(str[i]);
	}
}

//
//The STL algorithm way 
void toLowerCaseSTD(std::string &str)
{
	std::transform(str.begin(), str.end(), str.begin(), std::tolower);
}


int main()
{
	std::string test("ABCDEFG");
	toLowerCase(test);
	std::cout << test << std::endl;
	
	std::string test2("HIJKLMNO");
	toLowerCaseSTD(test2);
	std::cout << test2 << std::endl;

}