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Function for this

skittlesaddictx50v (47)
I have a basic program where you choose a number 0-9 and depending on what you choose you win money..
I know you can put this into an array, but could it be easier to make it into a function. If so how?

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cin >> selection;

if (selection == 0){
	user_winnings = 100;
}
if (selection == 1){
	user_winnings = 500;
}
if (selection == 2){
	user_winnings = 1000;
}
if (selection == 3){
	user_winnings = 0;
}
if (selection == 4){
	user_winnings = 10000;
}
if (selection == 5){
	user_winnings = 0;
}
if (selection == 6){
	user_winnings = 1000;
}
if (selection == 7){
	user_winnings = 500;
}
if (selection == 8){
	user_winnings = 100;
}
Disch (13742)
er, just copy/paste that code into a function. =P Maybe return the user_winnings value:

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int yourfunction()
{
  int selection;
  int user_winnings;

  // copy/paste the above code

  return selection;
}


But of course, as you said... this would be much better if you use a lookup table (array). I try to avoid long if chains like this:

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int user_winnings[9] = {
  100,
  500,
  1000,
  0,
  10000,
  0,
  1000,
  500,
  100
};

if((selection >= 0) && (selection < 9)) // make sure the user entered a valid selection
  return user_winnings[ selection ];
else
  // do something to indicate the user entered something invalid


EDIT: fixed function error
Last edited on
buffbill (467)
er, void yourfunction() isn`t meant to return a value is it?
Disch (13742)
you're absolutely right, buffbill. Modified original post to correct that.
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