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- When i start after building the program
When i start after building the program won't run
Any program I attempt to run without debugging, will run, the window pops up, and then closes itself immediately. Can anyone tell me why this happens? Or at least how I can remedy this problem?
Mind you I am using microsoft visual studio 2010
Mind you I am using microsoft visual studio 2010
Well it would help if you posted the source code (Use code tags!) but i think that its because it has nothing to pause it so it just runs then immediately closes
let's say i am trying to run a simple program such as this,
#include <stdio.h>
int main(void)
{
int i;
i=1;
while(i<=128){
printf("%d ", i);
i*=2;
}
return 0;
}
the output of course would be,
2,4,8,16,32,64,128
Am i forgetting to put something in the code?
#include <stdio.h>
int main(void)
{
int i;
i=1;
while(i<=128){
printf("%d ", i);
i*=2;
}
return 0;
}
the output of course would be,
2,4,8,16,32,64,128
Am i forgetting to put something in the code?
http://cplusplus.com/forum/beginner/1988/
Programs that use cout, cin, ... are meant to be run from a terminal. When you run them from outside of one, a terminal is created for the program and discarded when it's finished.
A Solution: write a batch/shell file that looks something like this:
Then run that instead.
Programs that use cout, cin, ... are meant to be run from a terminal. When you run them from outside of one, a terminal is created for the program and discarded when it's finished.
A Solution: write a batch/shell file that looks something like this:
@my_program.exe arg1 arg2 ... @pause |
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