simple arraycopy

[cidron]

EDITED: new problem
Hi kind people. Why does this not work? :(

#include <iostream>
using namespace std;


int main(){
    char A,B;
    char arr1[2] = {A,B};
    char copy[2];
    for(int i=0;i<2;i++){    //i want to make a copy of arr1
        copy[i]=arr1[i];
    }
            cout << copy[0] << copy[1]; //output wierd symbols :P
    return 0;
}

[z05DSL3A]

Line 9 should be copy[i] = arr1[i];

[cidron]

thanks,
i have edited the code (changed int with char). This does not work.

[jsmith]

It does work, it just doesn't do what you think it does.

Since copy is an array of characters, it outputs the characters represented by ASCII values 1 and 2. ASCII values 1 and 2 are unprintable characters.

Either change your array to int or change 1,2 to '1','2'

[cidron]

sorry, i forgot to correct line7:
char arr1[2] = {A,B};

And yes, it works if i put the " ' " around the letters:
char arr1[2] = {'A','B'};

but is the array for example sortable now? say i have
char arr1[20] = {'A','B','D','K','J','O',.............};
will i be able to sort the array alphabetically now?

[z05DSL3A]

And can you NOT change the original post in the future, it makes the replies nonsense to people coming to the thread later on.

[cidron]

Sorry Mr.
Will remember that.

[jsmith]

Doing char arr1[2] = { A, B }; doesn't make sense since A and B are both uninitialized variables. However, using the quotes makes an array of the literal characters which you could sort.