structures with pointers.find the output

[sibendudey]

#include<conio.h>
#include<stdio.h>

void main() {
struct st {
int i;
struct st *j;
}t1,t2;
clrscr();
t1.i=123;
t2.i=456;
t1.j=&t2;
t2.j=&t1;
printf("%d\n%d",*t2.j,*t1.j);
}


checked it with compiler
*t2.j=123
*t1.j=garbage value;
can anybody explain me why ?

[Cubbi]

What do you get after correcting the errors?

#include <stdio.h>

int main()  {
    struct st   {
        int i;
        struct st *j;
    }t1,t2;

    t1.i=123;
    t2.i=456;

    t1.j=&t2;
    t2.j=&t1;

    printf("%d\n%d\n", t2.j->i, t1.j->i);
}

I get 123 and 456, as you probably intended: http://ideone.com/JOFlQ

The errors were wrong return type of main, which wouldn't affect the output, and wrong arguments to printf, which results in undefined behavior.

PS: If your system is anything like this GCC/linux I tested on, printf() expects to see integer arguments in certain CPU registers: ESI for the first %d, EDX for the second %d. You're passing structs, which are stored on stack instead, and the registers contain whatever intermediate values they happen to have at this point of execution.

[Anthony Hernandez]

Oh I see the difference now.

Trying to call a pointer with " . " instead of " -> "

http://www.cplusplus.com/reference/std/new/operator%20new/