How do I use a variable within a string?

[Schmitty124]

Okay my problem is that I want to run a for loop that multiples the variable in the for loop by a number but that part of my code has to be within a string for the program I am running it in. So my question is is how do I declare this variable within that string in order to make the math work?

This is part of the code
for(int i=0;i<=5;i++)
{
T->Draw("g_p[0]-r_p[0]>>h1(100,-.07,.1)","r_FT[0]==1 && g_p[0]<1.35+.25 && g_p[0]>1.35-.25 && g_theta[0]<(0.0396+0.0792*i)+0.0396 && g_theta[0]>(0.0396+0.0792*i)-0.0396");
}
What i need is the variable I to be seen as a variable and change to numbers 0-5 for the 6 different times this code should be run

[modoran]

Convert first integer i to a string, hen use string concatenation methods. There is no direct way to do it as in interpreted languages like php, perl, etc.

[viliml]

So, sou need the string to command cast? One very, very, VERY stupid way is to change the file you are working on using file streams, becouse when you put a string in a file using file streams it will be a command, not a string. The only down-side i s that you would have to run the program twice.

[Schmitty124]

I found that if I rewrote it like this

for(int i=0;i<=5;i++)
{
T->Draw("g_p[0]-r_p[0]>>h1(100,-.07,.1)","r_FT[0]==1 && g_p[0]<1.35+.25 && g_p[0]>1.35-.25 && g_theta[0]<(0.0396+0.0792* %i)+0.0396 && g_theta[0]>(0.0396+0.0792* %i)-0.0396",i);
}

that the error changed so that I think it knows the i is a variable now but it gives me Invalid Syntax "*"

[Moschops]

I think your question is "How do I build a string out of a string and an integer"?

Here's some example code.

int i = 7;
string littleString("someWords");
string bigString = littleString + itoa(i) + littleString;