2D string array as parameter to function

Nanne (18)
Hi,

Is it possible to pass a 2D dynamic string array to a function as a parameter?

For.Ex:

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string stringArray2D[1][4]= {"Hello", "How", "Are", "You"};
string stringArray2D[1][3]= {"Hello", "How", "Are};
process2DStringArray(stringArray2D);


void process2DStringArray(string stringArray2D[][])
{

}


How can I make the parameter to take a generalised any size of 2D string array?

Thank you!
vlad from moscow (6539)
I do not see any sense in the constructions

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string stringArray2D[1][4]= {"Hello", "How", "Are", "You"};
string stringArray2D[1][3]= {"Hello", "How", "Are};


Why do you not use simply

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string stringArray2D[4]= {"Hello", "How", "Are", "You"};
string stringArray2D[3]= {"Hello", "How", "Are};


As for your question string stringArray2D[1][4] and string stringArray2D[1][3] are two different types. So you can not use one function with the same parameter. You can write a template function as for example

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template <size_t N>
void process2DStringArray( std::string ( *stringArray2D )[N], size_t m )
{
/* some code */
}



Or instead of a two-dimensional array you can use std::vector. For example

std::vector<std::vector<std::string>> v;
Last edited on
Nanne (18)
Ohh sorry! That's just a wrong ex.
I wanted to use multidimentional arrays as below

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string stringArray2D[2][4]= {"Hello", "How", "Are", "You", "I", "am", "fine", "ty"};
string stringArray2D[3][3]= {"Hello", "How", "Are", "good", "fine", "nice", "notGood", "NotFine", "NotNice"};
vlad from moscow (6539)
As I said in this case you should write a template function similar to that I showed.

Or it would be much better to use a vector. I will show you an example. It will not be compiled by MS VC++ but will be compiled with GCC 4.7.0

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#include <iostream>
#include <string>
#include <vector>


int main()
{
   std::vector<std::vector<std::string>> v = 
      { { "one", "two", "three" } };

   for ( const auto &x : v )
   {
      for ( const auto &s : x )
      {
         std::cout << s << ' ';
      }
   }
   
   std::cout << std::endl;
}
Last edited on
Nanne (18)
Thank you for suggestion and example too.
I use MS VC++ .. I will go with the first option :)

Thank you again!!
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