Pass by reference to pointers

[4ET0pfjN]

As I understand, pass by reference to pointers is another way to pass arguments; it's supposed to be cleaner than pass by pointers to pointers (since compiler does the work behind the scenes), but curious as how would I get it to insert at front of this linked list e.g.

struct node
{
	int data;
	node *next;
};

//using pass by ref to ptrs (i.e. cleaner version of pass by ptrs to ptrs) is ONLY available in C++
void insert_at_front(int data_, node *&front, node *&end)
{
	node *newNode = new node;
	node->data = data_;//NB: or you can use: (*node).data
	
	if ( front == NULL && end == NULL )
	{
		front = &node;
		end = &node;
		node->next = NULL;
	}
	else
	{
		node->next = front;
		front = &node; 
	}
}

int main()
{
  node *front = NULL; node *end = NULL;
  insert_at_front(88,front,end);//this doesn't work
  return 0;
}

[Cubbi]

from line 11 to line 22, the word 'node' (which is the type) should be replaced with the word 'newNode' (which is the name of the object).

[4ET0pfjN]

Typo there. But is that the only issue?

[Cubbi]

Not the only issue of course.

newNode is already a pointer, so lines like "front = &newNode;" should be "front = newNode;"

NULL is undefined (you have no #includes)

there is a memory leak -- I recomment tracking node ownership, e.g. make each node own the rest of the list, then memory clean up becomes automatic.