need help with some code

UserofC (3)
so i want this exit statement to go back to whatever the user was doing before but when you say yes it just exits out and doesn't redo the script. suggestions?

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bool exit()
{
	char exit;
	do{
		cout << "again? (y/n):\n";
		cin >> exit;
		if ( (exit == 'Y') || (exit == 'y') )
    return true;
		
 } while ( (exit != 'N') && (exit != 'n') );

 return false;

 }

ascii (1062)
How are you calling this function?

And the way it's currently set up, if they say yes, you're telling the program to exit. I think you mean to return false on line 8 and return true on line 12.
UserofC (3)
i am calling the function at the end of main() like so:

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if (ans == 1)
		Print_out(n);
	if (ans == 2)
		Array(b);
	if (ans == 0)
		exit(0);
	exit();
	
	char ch;
	cin >> ch;
	return 0;
ascii (1062)
Well you're currently only telling it to call the function once. You're calling exit(), and then not doing anything with its return value.

You'll probably want to put it into a loop like this:
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do {
    // your actually program goes here
} while(exit());
UserofC (3)
sweet! thank you. the true/false was in the right place i just had to put that do loop in the main().
ascii (1062)
Yes, I was confused as to how you were calling it in my first post, you had it right before.

Glad to help, anyhow.
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