Target each character of a string

[Sspangler]

Im trying to change a hexadecimal number to a decimal number and the only problem i have is that i don't know how to compare one character in the string to another character. i know you can compare whole strings but i cant find anything to compare just one character at a time. If anyone knows how to or if its even possible i would appreciate it.

[Zhuge]

I think you need to give a little more detail. string[i] will give you the the (i-1)-th character of the string.

[Sspangler]

Thats what i thought but i didnt seem to work maybe its something else

for (int i = 0; i < length; i++)
	{
		if (hex[i] == 'A')
			sum += 160;
		else if (hex[i] == 'B')
			sum += 176;
		else if (hex[i] == 'C')
			sum += 192;
		else if (hex[i] == 'D')
			sum += 208;
		else if (hex[i] == 'E')
			sum += 224;
		else if (hex[i] == 'F')
			sum += 240;
		else if (hex[i] == 'G')
			sum += 256;
		else 
			sum += hex[i];
	}

i assumed it would work this way it would check each character and decide what it need to add

[Zhuge]

I think your problem is that you are not summing properly. Your summing code implies 'A' is worth 160₁₀ no matter where the 'A' appears in the hex value. In other words, you are saying that 0xAB = 160+176 = 0xBA = 176+160, which is clearly wrong. You need to figure out the actual value of the hex digit based on its significance (position in the number).

[Sspangler]

O thats right i forgot about that. I feel dumb now. thanks for reminding me.