Any way to move this function definition out of the struct body?

[Gladdok]

I got a couple of funny errors that I wasn't sure how to deal with in the following situation:

template <int S> struct Mytempstruct
{
    struct Iterator;
    int x;
};

template <int S> struct Mytempstruct<S>::Iterator
{
    int p;

    int foo();
    Iterator& operator ++();
};

template <int S> int Mytempstruct<S>::Iterator::foo() { return 0; }

template <int S> Iterator& Mytempstruct<S>::Iterator::operator ++()
{
    ++p;
    return *this;
}

The definition of the foo() function is fine.

The definition of operator ++, however generates an error that the return type Iterator& is not defined.

If it is instead written as:

template <int S> Mytempstruct<S>::Iterator& Mytempstruct<S>::Iterator::operator ++()
{
    ++p;
    return *this;
}

The error then becomes that the compiler expected the keyword 'typename' somewhere in the head of the definition...I tried the following

template <int S> typename Mytempstruct<S>::Iterator& Mytempstruct<S>::Iterator::operator ++()

but that seemed to cause more confusion from the compiler.

When I move the function body into the struct definition, however, it works fine. Not the end of the world, especially since in the real code the function is only a few lines, but it clutters up the interface.

Thanks for looking

[vlad from moscow]

What compiler do you use?

This definition

template <int S> 
typename Mytempstruct<S>::Iterator & Mytempstruct<S>::Iterator::operator ++()
{
    ++p;
    return *this;
}

is compiled without errors by MS VC++ 2010.

[Gladdok]

You're right it does compile...I must have either made a mistake or not written to file before re-building. :)