I need some help working on a program. I am to pass 2-10 numbers which calculate an average. I don't have to pass all the numbers but have to pass at least 2. I can pass either all integers or all float values. Is anyone willing to help me in the right direction with this program?
Just sum all the numbers as you get them from the user (no need to use an array or anything). The average would then be sum / n, where n would be the amount of numbers entered. You'll need to cast one of the operands to a float in the average calculation to avoid truncation.
int main ()
{
int sum = 0;
int average = 0;
int score [10];
int k;
int avg(int a[])
//int sum = 0;
// int average = 0;
for (k = 0; k<10; k++)
{
cout <<"Enter score for 10 test:"<< (k+1) <<endl;
cin>> score [k];
average = avg(score)
sum = sum + score[k];
}
average = sum/10;
for (k=0; k<10; k++)
cout<<"score for test:"<<(k+1)<<"is"<<score[k]<<endl;
}
int avg (int a[size])
{
cout<<"The average for all 10 test is"<<average<<endl;
return 0;
}
Would This work or not? I understand some parts but some I don't so any help is appericated!!
this would only do the avg for integers ... like 8, 6, 10 not 8.5 , 7.3 or anything like that ... and if i'm not wrong ( and i'm pretty sure i'm not)you must declare functions outside any other function ... so declaring int avg(int a[]) inside main() isn't correct
#include <iostream>
usingnamespace std;
int main()
{
float currScore ;
float score = 0 ;
//get number of grades
short k;
cout <<"how many scores do you want to enter ? \n" ;
cin>> k ;
for (int i=0; i<k; i++) //you will get all the k scores like this
{
cout<<"score for test:"<<(i+1)<<"is " ; /*by this you request the user to input a new score*/
cin>> currScore ;
/*add the last score that the user inputed to the total score so you can divide it later */
score += currScore ; // this is the same as score = score + currScore ;
}
score = score / k ; /*by dividing score to k you will get the average*/
cout << "The average for all the " << k <<" tests is " <<score <<endl ;
return 0 ;
}