scoring a blackjack hand

idks16 (17)
i'm making a program that scores a blackjack hand but i don't know how to make ten, jack, queen, and king to have a value of 10 when the user has one of these in their hand.
this is my code:
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#include <iostream>
using namespace std;
int main()
{
    char a, total_cards;
    int total, c2, c3, c4, c5, c6, c7, c8, c9;
    const int t=10, j=10, q=10, k=10;
    bool cards;

    
    do
    {
    cout<<"How many cards do you have in your hand?\n";
    cin>>total_cards;
    switch (total_cards)
    {
          case '2':
               cout<<"You have 2 cards, what are they?\n";
               cout<<"what is the first card?\n";
               cin>>c2;
               cout<<"what is the second card?\n";
               cin>>c3;
               if (c2=a)
               c2==1;
               total=c2+c3;
               cout<<endl<<"The value of your hand is: "<<total;
               break;
          case '3':
               cout<<"You have 3 cards, what are they?\n";
               cout<<"what is the first card?\n";
               cin>>c2;
               cout<<"what is the second card?\n";
               cin>>c3;
               cout<<"what is the third card?\n";
               cin>>c4;
               total=c2+c3+c4;
               cout<<endl<<"The value of your hand is: "<<total;
               break;
          case '4':
               cout<<"You have 4 cards, what are they?\n";
               cout<<"what is the first card?\n";
               cin>>c2;
               cout<<"what is the second card?\n";
               cin>>c3;
               cout<<"what is the third card?\n";
               cin>>c4;
               cout<<"what is the forth card?\n";
               cin>>c5;
               total=c2+c3+c4+c5;
               cout<<endl<<"The value of your hand is: "<<total;
               break;
          case '5':
               cout<<"You have 5 cards, what are they?\n";
               cout<<"what is the first card?\n";
               cin>>c2;
               cout<<"what is the second card?\n";
               cin>>c3;
               cout<<"what is the third card?\n";
               cin>>c4;
               cout<<"what is the forth card?\n";
               cin>>c5;
               cout<<"what is the fifth card?\n";
               cin>>c5;
               total=c2+c3+c4+c5+c6;
               cout<<endl<<"The value of your hand is: "<<total;
               break;
          default:
                  cout<<"You must have between 2-5 cards in your hand\n";
    }
    }while (cards);
    
    
    cin>>c3;
    
    return 0;
}
liquidfuzz (78)
Eh 10 if player has one dressed card. Isn't jack queen and king always 10? That would make the question, what to do with aces if there's more than one in hand. Or..? Just an idea, no elegant solution:

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if(player.hand() > 21){
  //use different ace cards
  ace1 = 1;
  ace2 = 11;
  if(player.hand() > 21){
    //busted
  } else {
    //keep playing
  }
}
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