Classname* variableName = (Classname*) variableName2

[bentleykf]

Hi Guys,

I've taken it upon myself to learn C++ and I think I've got a pretty good understanding of pointers after a few days of research, but I'm curious about the above statement (Found at http://msdn.microsoft.com/en-us/library/ms810620 : Appendix A->in the CDXInput::DIEnumDevicesProc() function). Classname* variableName seems to make sense to me. You're creating a pointer variable to a class object. Its the statement on the right hand side of the equals confuses me: (Classname*) variableName2. Why would you need to encapsulate the pointer and the Classname on the right hand side of the equals?

thanks in advance for your responses.

[zb0S216C]

It's a c-style cast. It's used to cast the type associated with the identifier (after the parentheses) to the type specified within the parentheses. It seems as though Microsoft favours c-style casts instead of C++'s casting operators. Sad, really.

_Wazzak