1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
|
#include <iostream>
#include "conio.h"
#include <string>
#include <cmath>
#include <math.h>
using namespace std;
// this variable is to choose what function a person wants to do
int mainfunction = 0;
/* !!!!!!!!!!These next variables are for the division of polynomials function !!!!!!!!!!!!!!!!!*/
int checkinputspecial;
int firstchoice = 0; // determines degree of divident (thing being divided)
int secondchoice = 0; // determines degree of divisor
int dive [7] = { 0, 0, 0, 0, 0, 0, 0 } ; // this is your dividend, if its a 3 degree polynomial, you will only use 3 of the alloted variables etc.
int divi [6] = { 0, 0, 0, 0, 0, 0 }; // this is your divisor, to be used for any degree divisor
int quo [6] = { 0, 0, 0, 0, 0, 0 };// this is going to be your quotient that ends up on top of the dividend
int line [8][7]; /* These are your subtraction lines. the first box denotes sequence from top to bottom.
second box denotes space in that line from left to right, as if you were doing this division by hand
and drew a graph around the various inputs under the dividend*/
int abso [5];// these are to be used for when you need to convert a 'line [x][x]' into its absolute value
int rem2 [3] ;// no use yet
int result [7] ;// no use yet
int check_input1 = 1;// to find out if dive input is correct
int check_input2 = 1;// to find out if divi input is correct
int dive1 [5];// not used yet
/* !!!!!!these next variables are for the quadratic formula function!!!!!!!!!!!!!*/
float a, b, c;
double d = (b / -1);
double e = (b * b);
double f = 4 * a * c;
double t = e - f;
double y = sqrt(t / -1);
double u = d + y;
double g = 2 * a;
double h = (d + y) / g;
/* these variables are for the circle function!!!!!!!! */
int circlefunction;
double radius = 0;
double PI = 3.1415932;
double circumferance = (2 * PI * radius);
double area = (PI * (radius * radius));
double timesaround = 0;
double time = 0;
double totaldistance = 0;
double speed = 0;
int main()
{
cout << " hello \n \n \n " << endl;
cout << " welcome to Johnny's calculator \n" << endl;
cout << " this calculator can do a few things and more are always being added \n \n" << endl;
cout << " right now we can either \n" << endl;
cout << "1.) use the quadratic formula to find the zeroes of a quadratic polynomial \n " << endl;
cout << "2.) divide polynomials of various degree's into one another \n" << endl;
cout << "3.) do equations based on the relations of a circle \n \n " << endl;
cout << "please choose what you would like to do ( 1 2, 3 ) " << endl;
cin >> mainfunction;
cout << " \n \n \n \n \n \n " << endl;
if (mainfunction < 1 && mainfunction > 3)
{
return main();
}
if (mainfunction == 1)
{
cout << " today we will find the zeroes of a quadratic using the quadratic formula" << endl;
cout << " it will be in this form. " << endl;
cout << " \n \n Ax^2 + Bx + C \n \n \n" << endl;
cout << "please enter your 'a' term" << endl;
cin >> a;
cout << "please enter your b term" << endl;
cin >> b;
cout << "please enter your constant (c term)" << endl;
cin >> c;
cout << "your polynomial is " << a <<"x^2 +" << b << "x +" << c << endl;
double d = (b / -1);
double e = (b * b);
double f = 4 * a * c;
double t = e - f;
double y = sqrt (t / -1);
double u = sqrt (t);
double g = 2 * a;
if (t < 0)
{
cout << " the zero's of your polynomial are " << d << " +/- " << y << "i" << "/" << g << " \n \n " << endl;
cout << "this reduces to " << d / g << " + " << y << "i" << " / " << g << " \n \n " <<endl;
cout << "and " << d / g << " - " << y << "i" << "/" << g << " \n \n \n \n \n \n \n \n" << endl;
system("PAUSE");
}
if (t > 0)
{
cout << " the zero's of your polynomial are " << d / g << " +/- " << u / g << " \n \n " << endl;
cout << "this reduces to " << (d / g) + ( u / g) << " and " << (d / g) - (u / g) << " \n \n \n" << endl;
system("PAUSE");
}
return main();
}
if (mainfunction == 2)
{
cout << " today we will be dividing two polynomials together \n" ;
cout << " \n ";
cout << " it will be in this form; \n" ;
cout << " \n ";
cout << " ax^3+ bx^2+ cx+ d / ax^2+bx+c \n " ;
cout << " \n" ;
cout << "with varying numbers for both the degree of the polynomial and the coeffecients \n" ;
cout << " \n";
cout << " please select the degree of your dividend ( 2 < x < 4 ) \n" << endl;
cout << " ( the dividend is the number being divided into ) " << endl; // select degree of dividend
cout << " ( the divisor is the number the dividend is divided by ) " << endl;
cout << " \n ";
cin >> firstchoice;
if (firstchoice < 2 || firstchoice > 4) // incase they enter a degree to high for my programming skills
{
cout << endl << "please choose a dividend of degree 3 or 4 "; cin >> firstchoice;
}
if (firstchoice == 3)
{
cout << "what is the degree of your divisor? (1 or 2) \n";
cin >> secondchoice;
if (secondchoice == 1) /* this is for a 3rd degree plynml being divided by a 1st degree plynml, in the form "Ax+B"*/
{
cout << "you said your dividend is a 3rd degree polynomial, this will be in the form \n" ;
cout << " \n ";
cout << " Ax^3 + Bx^2 + Cx + D \n " ;
cout << "D is your constant term \n";
cout << " \n ";
cout << "please enter in the corresponding coeffecients as they logically \n " << endl;
cout << "appear on screen. numbers must be whole intergers\n " << endl ;
cout << " \n " << endl;
cout << "please enter the proper coeffecients for the corresponding terms below \n";
cout << " \n ";
cout <<" Ax^3 + Bx^2 + Cx + D \n \n \n";
cout << " \n ";
cout << "A term ="; cin >> dive [0]; cout << dive [0] << endl;
cout << " \n ";
cout << "B term ="; cin >> dive [1]; cout << dive [1] << endl;
cout << " \n ";
cout << "C term ="; cin >> dive [2]; cout << dive [2] << endl;
cout << " \n ";
cout << "D term (constant) ="; cin >> dive [3]; cout << dive [3] << endl;
cout << " \n ";
cout << "your polynomial is \n";
cout << " \n ";
cout << " " << dive [0] << "x^3 + " << dive [1] << "x^2 + " << dive [2] << "x + " << dive [3] << endl;
cout << "is this correct (0 for NO, anything else for YES)" << endl;// to make sure input is correct
cin >> check_input1;
cout << " \n \n \n \n \n \n \n " << endl;
if (check_input1 == 0)
{
cout << "re-enter your A,B,C, and D term, one by one. hitting enter after each one \n" << endl;
cin >> dive [0];
cin >> dive [1];
cin >> dive [2];
cin >> dive [3];
cout << "your dividend polynomial is \n";
cout << dive [0] << "x^3 + " << dive [1] << "x^2 + " << dive [2] << "x + " << dive [3] << endl;
cout << " \n \n \n \n \n \n \n " << endl;
check_input1 = 2;/* makes it so whatever they enter in the second time gets automatically passed onto the divisor
input*/
}
|
