How to terminate input and go directly to output?

[Tatipu]

hey guys,

I'm almost done with my program but I have one problem...

I can't terminate my input the correct way and go to the output.
My input is
string w;
getline(cin, w);
and when the user inputs " @@@ " and then enter, it's supposed to terminate.


Any ideas how to do that? Or do I need to change my input form to cin?

[Computergeek01]

You just have to test your string variable, "w" in this case, for the " @@@ " value. If it matches then you break the loop. Personally I'd use a do while(...) loop for this.

[Tatipu]

I do. and I do have a do while loop.

do {
int bindex = 0, eindex = 0, i = 0, wlen = 0;
getline (cin,w);
toLowerCase(w);
removePunct(w, i);
for (i = bindex; i < w.length(); i++){
    if (w[i] == ' '){
    w2 = w.substr(bindex, wlen );
    bindex = i+1;
    wlen = 0;
    count++;
    find.search(w2, count, found);  
}
else wlen++;
}}    
while (w.compare("@@@") != 0);

Just pretend those have variable declarations already. ..
I input @@@ at the end but Ii'm thinking since it's getline, it won't notice the @@@?
Because when I put @@@ by itself on a new line, it will terminate. Other than that, it won't terminate when it's on the same line as my other input

[Computergeek01]

Right it has to be an exact match for the "compare(...)" string member function to return 0. If you are trying to test for "@@@" INSIDE of the target string you could use the "search(...)" STL member function: http://www.cplusplus.com/reference/algorithm/search/

[Tatipu]

Alright, thanks I'll look into it!