Using Getline Problem.

[Tatipu]

Alright so I recently learned getline, from a tutorial and I looked it up for examples on this website and
This is the example provided from the website:

// istream getline
#include <iostream>
using namespace std;

int main () {
  char name[256], title[256];

  cout << "Enter your name: ";
  cin.getline (name,256);

  cout << "Enter your favourite movie: ";
  cin.getline (title,256);

  cout << name << "'s favourite movie is " << title;

  return 0;
}

my code:

char AiDee[8], AitemName[20], AitemProducer[20];
int number;
     cout<<"Enter ID: ";
     cin >> AiDee;
     cout<<"Enter Item Name: ";
     cin.getline (AitemName,20);
     cout<<"Enter Producer: ";
     cin.getline (AitemProducer,20);
     cout<<"Enter Quantity: ";
     cin >> number;

My output is like this :

Enter ID: 49583
Enter Item Name: Enter Producer:

Why does it skip line? What did I do differently than the example?
(IF I took out both other

cin>>

then It would work o-o. )

[helios]

Using operator>>() to read from std::cin sucks. Its behavior is completely unintuitive: it always leaves a newline in the input buffer, so if you mix reading methods, something is bound to go wrong. Use exclusively getline(). In fact, I'd recommend std::getline() plus std::string.

[Tatipu]

How do you use getline()?

I tried from a tutorial
and he did
string x;
getline(cin, x);

I tried this and I got an error before saying "no matching function for call to `getline(std::istream&, char[20])'"

My code, I didn't know if this was right:

getline(cin, AitemName);

[ledien]

char AiDee[8], AitemName[20], AitemProducer[20];
int number;
cout<<"Enter ID: ";
cin >> AiDee;

cin.ignore(1);


cout<<"Enter Item Name: ";
cin.getline (AitemName,20);
cout<<"Enter Producer: ";
cin.getline (AitemProducer,20);
cout<<"Enter Quantity: ";
cin >> number;

[Tatipu]

Omg. Thank you so much! You're a life saver! :D .

I don't know what it does but it works ^_^!!!!