Cell Phone Bill.

[Ralphus629]

Hey guys this is my first time posting so please bear with me.

So I have this assignment for my C++ class to write a program that calculates and prints my cell phone bill.

I have most of the code done but my issue is the input of the account number. My code is:

        cout << "Please enter your 6-digit account number: ";  
	cin >> accountNum;
	cout << endl;

	 if (accountNum > 100000)
		{
		  cin >> accountNum; 
		  cout << endl;
		}
	 else 
	    {
		  cout << "Invalid entry, please re-enter a 6-digit account number: "; 
		  cin >> accountNum;
		  cout << endl; 
	    }

How can I restrict the input to only 6 digits without any accounts starting with leading 0's such as "000265"?

p.s: how do I get the program to print output to a file? Thanks

[tfityo]

Why don't check if accountNum < 1000000

[Ralphus629]

Either "<" or ">" the program gets stuck. According to the instructions, I must keep the 6 digit account without it starting with a 0. The expression for the if statement could be wrong.

[tfityo]

you have two conditions and you can combine them with AND operator:
if (accountNum > 99999 && accountNum < 1000000)

All numbers satisfying these condition lie in [100000-999999], they all have 6 digits.

[Ralphus629]

I just changed it and the output gets stuck giving my input, this is my whole program. Where could I've gone wrong?

#include <iostream> 
#include <iomanip>
#include <string>

using namespace std; 

const double rService = 10.00; 
const double rPerMinute = 0.20;
const double pService = 25.00;
const double pPerMinuteDay = 0.10;
const double pPerMinuteNight = 0.05;


int main()

{
	
	int regMinutes;
	int dayMinutes;
	int nightMinutes; 
	int accountNum;
	char serviceType;
	double amountDue; 
	

	cout << "Please enter your 6-digit account number: ";  
	cin >> accountNum;
	cout << endl;
	 if (accountNum > 99999 && accountNum < 999999)
		{
		  cin >> accountNum; 
		  cout << endl;
		}
	 else 
	    {
		  cout << "Invalid entry, please re-enter a 6-digit account number: "; 
		  cin >> accountNum;
		  cout << endl; 
	    }

	cout << "Enter a service code: R or r (Regular), P or p (Premium): ";
    cin >> serviceType;
	cout << endl; 
		
	switch (serviceType)
	 {
	 case 'r':
	 case 'R':
		 cout << "Enter the number of minutes used: ";
		 cin >> regMinutes; 
		 cout << endl; 

	  if (regMinutes > 50)
	     {
		   amountDue = rService + ((regMinutes - 50) * rPerMinute);
	     }
      else
        amountDue = rService;

     break;
	 
	 case 'p':
	 case 'P': 
		 cout << "Enter the minutes used for the day: ";
		 cin >> dayMinutes; 
		 cout << endl;     

      if (dayMinutes > 75) 
		  amountDue = pService + ((dayMinutes - 75) * pPerMinuteDay);
	  else
          amountDue = pService;

	     cout << "Enter the minutes used for the night: ";
     	 cin >> nightMinutes; 
		 cout << endl;
      
      if (nightMinutes > 100)
		  amountDue = pService + ((nightMinutes - 100) * pPerMinuteNight);
	  else 
		  amountDue = pService; 

	  break;

	 }

	 cout << "Account Number: " << accountNum << endl; 
	 cout << "Type of Service: " << serviceType << endl; 

	 switch (serviceType)
	     {
		 case 'R':
		 case 'r':
		 cout << "Number of minutes used (if regular): " << regMinutes << endl; 
		 break;
	 
		 case 'P':
		 case 'p':
	     cout << "Number of minutes used during the day (if premium): " << dayMinutes << endl; 
 	     cout << "Number of minutes used during the night (if premium): " << nightMinutes << endl; 
 
		 break;

	     }

	 cout << fixed << showpoint; 
	 cout << setprecision(2);
	 cout << "Amount Due = $ " << amountDue << endl;

	return 0;
	
}

[tfityo]

I think that you are stuck here

	 if (accountNum > 99999 && accountNum < 999999)
		{
		  cin >> accountNum; 
		  cout << endl;
		}

In the line cin >> accountNum; the program asks for a new phone number. Maybe you should write something like it:

	 if (accountNum > 99999 && accountNum < 999999)
		{
		  cout << "You entered " << accountNum; 
		  cout << endl;
		}