evaluating a expression

[lifnajos]

int k =8;
int b = (k++ -k++ - k++);

how this expression is evaluated?

[helios]

http://www.parashift.com/c++-faq-lite/misc-technical-issues.html#faq-39.15

[zb0S216C]

It's hard to predict since the standard doesn't guarantee which increment expression is evaluated first.

Place a set or parentheses around each k++. Within the context of expressions, the uses of parentheses overrule the precedence of the used operators, meaning that the parenthesized expressions are evaluated first.

You should note the difference between N++ and ++N. N++ uses the value within N then increments it. ++N increments N then uses it. Your expression should look like this:

int B( ( K++ ) - ( K++ ) - ( K++ ) );

_Wazzak

[helios]

Place a set or parentheses around each k++. Within the context of expressions, the uses of parentheses overrule the precedence of the used operators, meaning that the parenthesized expressions are evaluated first.

What does that accomplish? ( ( K++ ) - ( K++ ) - ( K++ ) ) and (k++ -k++ - k++) are equivalent expressions.

[Duthomhas]

Google around "sequence points". Parentheses do not indicate sequence points.