Ternary Operator Problems

I've written a shift cipher encryption program and just for educational purposes I wanted to see if I could reduce all my if then statements to a big long ternary operator. I've reduced it by several lines but have been unable to get the entire thing on one line. I'm thinking it should be possible but I can't quite get the syntax right.

Here is what I started with:
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if (y < 65 || y > 90 && y < 97 || y > 122)
     xy = y;
else if (y < 123 && y > 96)
{
     if (y + sVal < 123 && y + sVal > 96) //LCASE1
          xy = y + sVal;
     else if (y + sVal < 97) //LCASE2
	  xy = y + sVal + 26;
     else if (y + sVal > 122) //LCASE3
	  xy = y + sVal - 26;
}
else if (y < 91 && y > 64)
{
     if (y + sVal < 91 && y + sVal > 64) //CAPS1
	  xy = y + sVal;
     else if (y + sVal < 65) //CAPS2
	  xy = y + sVal + 26;
     else if (y + sVal > 90) //CAPS3
	  xy = y + sVal - 26;
}



Here is what I've since reduced it down to (I want to get this on one line):
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if (y < 65 || y > 90 && y < 97 || y > 122)
     xy = y;
else if (y < 123 && y > 96)
     xy = (y + sVal < 123 && y + sVal > 96) ? y + sVal : (y + sVal < 97) ? y + sVal + 26 : (y + sVal > 122) ? y + sVal - 26 : false;
else if (y < 91 && y > 64)
     xy = (y + sVal < 91 && y + sVal > 64) ? y + sVal : (y + sVal < 65) ? y + sVal + 26 : (y + sVal > 90) ? y + sVal -26 : false;
				



And here's the entire program to stick it in:
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#include <iostream>
#include <string>
#include <fstream>

using namespace std;


int main()
{
	string line;
	string crypt = "";
	string iFile;
	string oFile;
	int sVal;
	cout << "Input source file: ";
	cin >> iFile;
	cout << "Input destination file: ";
	cin >> oFile;
	cout << "Input shift value: ";
	cin >> sVal;
	cout << "Reading from file: " << iFile << endl;
	const char* v = iFile.c_str();
	ifstream myfile(v);
	cout << "Writing to file: " << oFile << " with shift value of: " << sVal << endl;
	const char* z = oFile.c_str();
	ofstream myofile(z);
	if(myfile.is_open())
	{
		while(!myfile.eof())
		{
			getline (myfile,line);
			//cout << "line gotten is: " << line << endl;
			for(unsigned int i=0; i < line.length(); i++)
			{
			     char y = (line.at(i));
			     char xy = 12;
                             /** Code starts here **
			     if (y < 65 || y > 90 && y < 97 || y > 122)
				  xy = y;
			     else if (y < 123 && y > 96)
				  xy = ((y + sVal < 123 && y + sVal > 96) ? y + sVal : (y + sVal < 97) ? y + sVal + 26 : (y + sVal > 122) ? y + sVal - 26) : false
			     else if (y < 91 && y > 64)
				  xy = ((y + sVal < 91 && y + sVal > 64) ? y + sVal : (y + sVal < 65) ? y + sVal + 26 : (y + sVal > 90) ? y + sVal -26 : false);
                             ** Code ends here **/			     
                             crypt += xy;
			}
			myofile << crypt << endl;
			crypt = "";
		}
		myfile.close();
	}
	else cout << "Unable to open file" << endl;
	cout << "EOF" << endl;
}
Just use some some more () around it to specifiy what everything should be and it should be fine...Ex:

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if(x == 2) {
   x = 1;
} else if(x == 1) {
   x = 0;
} else {
   x = 5;
}
//becomes
(x == 2) ? x = 1 : (x == 1 ? x = 0 : (x = 5));
I'm happy to report that I solved my problem. I have included the finalized code below for anyone who is interested. =)


From This:
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if (y < 65 || y > 90 && y < 97 || y > 122)
	xy = y;
else if (y < 123 && y > 96)
{
	if (y + sVal < 123 && y + sVal > 96) //LCASE1
		xy = y + sVal;
	else if (y + sVal < 97) //LCASE2
		xy = y + sVal + 26;
	else if (y + sVal > 122) //LCASE3
		xy = y + sVal - 26;
}
else if (y < 91 && y > 64)
{
	if (y + sVal < 91 && y + sVal > 64) //CAPS1
		xy = y + sVal;
	else if (y + sVal < 65) //CAPS2
		xy = y + sVal + 26;
	else if (y + sVal > 90) //CAPS3
		xy = y + sVal - 26;
}		



To This:
xy = (y < 65 || y > 90 && y < 97 || y > 122) ? y : (y < 123 && y > 96) ? ((y + sVal < 123 && y + sVal > 96) ? y + sVal : (y + sVal < 97) ? y + sVal + 26 : (y + sVal > 122) ? y + sVal - 26 : false) : (y < 91 && y > 64) ? ((y + sVal < 91 && y + sVal > 64) ? y + sVal : (y + sVal < 65) ? y + sVal + 26 : (y + sVal > 90) ? y + sVal -26 : false) : false;
Why?
Code obfuscation I suppose.
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