Arguing arrays in functions//Getting output issue and can't figure the problem with my code..PLEASE_HELP.

[mbede]

I get the output:
Martin's Hardware
-----------------
Part No. Price Count Remaining
-858993460 -858993460 -858993460
-858993460 -858993460 -858993460
-858993460 -858993460 -858993460
-858993460 -858993460 -858993460
-858993460 -858993460 -858993460


DataMaster options:
1. Add an Item.
2. Print Report.
3. Exit Program.
Enter 1, 2 or 3 to select option-->


Seems that the array is getting input into but the print output is all "blamo'ed" please help me.
*************************************************************/
#include <iostream>
#include <iomanip>
#include <string>

using namespace std;

int menu();
void addItem(int[],int[],int[], int, int);
void printReport(int[],int[],int[], int, int);

int main()
{
const int size = 5;
int partNumber[size];
int price[size];
int remaining[size];
int count = 0;
int addItem_option = 1,
printReport_option = 2,
exit_option = 3,
option;
option = menu();

if (option == 1)
addItem(partNumber,price,remaining, count, size);

if (option == 2)
printReport(partNumber,price,remaining, count, size);

else
exit(0);

system("pause");
return 0;
}


/************************* menu **************************
NAME:menu
PURPOSE: Select options
CALLED BY: main()
INPUT: int partNumber, int price, int remaining, int count, int size.
OUTPUT: int option
****************************************************************************/
int menu()
{
int option;

cout << "\tDataMaster options:\n "
<< "\t 1. Add an Item.\n"
<< "\t 2. Print Report.\n"
<< "\t 3. Exit Program.\n"
<< "\tEnter 1, 2 or 3 to select option--> ";
cin.clear();
cin >> option;

while ((cin.fail()) || (option < 1) || (option > 3))

{
cin.clear();
cin.ignore(1000,'\n'); // Ignore up to 1000 characters input
cout << "\n\n\tInput failure, you must enter a #: 1,2 or 3 -->";
cin >> option;
}

system("cls");
return option;

}

/************************* addItem **************************
NAME:addItem
PURPOSE: input values into array
CALLED BY: main
INPUT: int partNumber, int price, int remaining, int count, int size.
OUTPUT: none
****************************************************************************/

void addItem(int partNumber[],int price[], int remaining[], int count,int size)
{
for (count = 0; count < size; count++)
{
cout << "Enter the part # of the item: ";
cin >> partNumber[count];
cout << "\nEnter the price of the item: ";
cin >> price[count];
cout << "\nEnter quantity remaining: ";
cin >> remaining[count];
system("cls");
main();

}

}


/************************* printRecipt **************************/
NAME:printRecipt
PURPOSE: Select options
CALLED BY: (what is callING function?)
INPUT: (parameters function receives)
OUTPUT: (values that are returned)
****************************************************************************/
void printReport(int partNumber[],int price[], int remaining[], int count, int size)
{

cout << "\t\t\tMartin's Hardware\n"
<< "\t\t\t-----------------\n"
<< "\tPart No.\tPrice\t\tCount Remaining\n";
for (count = 0; count < size; count++)
cout << "\t"<< partNumber[count] << "\t"<< price[count] << "\t" <<remaining[count] << "\n";

cout << "\n\n";
main();
}

[shacktar]

You're getting garbage printed out because you're recursively calling main() from within addItem()/printReport(). When you type in option 2, it prints the values which are currently on the stack. Instead, you should be calling menu() and addItem()/printReport() in a loop until the user decides to quit.

[mbede]

Are you suggesting to put the addItem and the printReport in the same function

[shacktar]

No, I'm suggesting that you don't call main() from them. Instead, you should use a loop within main.