Having issues with the getting the string to read the location path ... please help im a bit new

[Togaboy1108]

#include <fstream>
#include <sstream>
#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
char ch, word=' ';
int ch_cnt=0, space_cnt=0, word_cnt=0;

//if( word >>'a');
//word_cnt--;
ifstream inFile; // Identify the file

string path;

cout<< "Enter the location of the file.";
cin>> path;

inFile.open("path");
// Associate the file name with a physical
// file on the disk.

if( inFile.fail() )
{
cout<<"Either you or the machine are having issues! The test results have\n"
"determinded that you are the error.\n";
getch();
exit(1);
}
// If we get here, the file is open


// THE BATCH PROCESSING LOOP
ch = inFile.get(); // Read

while( !inFile.eof() ) //Test for end of file
{
cout<<ch; // Process
ch_cnt++;

if( isspace(ch))
space_cnt++;

if( !isspace(word)&& isspace(ch))
word_cnt++;



word=ch;
ch=inFile.get(); //Read
}

if(!isspace(word))
word_cnt++;



cout<<"\n\n|"<<word<<"|\n\n";

cout<<"\n The character count is "<<ch_cnt;
cout<<"\n \n The space count is "<<space_cnt;
cout<<"\n \n The word count is "<<word_cnt;
inFile.close();


cout<<"\n\nNormal termination.\n";
getch();
return 0;
}

[Azagaros]

Are we trying to read a directory on the disk? Or are we trying to read a file named 'path'?

What you have done is tried to open a file named 'path'. It looks like I similar project I helped someone else on in this link, which you are showing some of the same logic problems.
http://www.cplusplus.com/forum/general/51305/

If I read the code a little further it should be:

inFile.open( path.c_str() ); // note the difference to inFile.open("path"); 

the other thing I would change is :

char ch, word=' ';
int ch_cnt=0, space_cnt=0, word_cnt=0;

to:

char ch;
string word;
int ch_cnt=0, space_cnt=0, word_cnt=0;

I don't need string stream for this problem.

hope that points you in a direction.

[Togaboy1108]

the idea behind my string was to allow people to type the path"directory" of the text file... i tired putting it the location I.E C:\test.txt but it resulted in an infile fail closing the program

[Azagaros]

well you need to access the contents of the string of path, and "path" is an indication of the file name "path", which you don't want. And that is what I gave you in my example.

if you followed some of the code examples and handled some of them differently I would see something like I give an example here.

string path;
char inchar;

cout<< "Enter the location of the file.";
cin>> path;

if( inFile.open( path.c_str() ) )
{
       while (!inFile.eof())  // watch for the end of file.
       {
              inFile >> inchar;  // read a character in.
              cout << inchar;  // print the character read in...
       }
}
else
{
       cout << "I couldn't open the file for some reason!!" << endl
}

I guess I would expect to see something like this pattern in your code to know if i had a problem with the file.