#include<iostream>
usingnamespace std;
int main()
{
int n,x,i,a[100],flag=0;
cout<<"Enter a Number ";
cin>>n;
cout<<"Enter "<<n<<" numbers";
for(i=0;i<n;i++)
cin>>a[i];
cout<<"Enter a Number to be search ";
cin>>x;
for(i=0;i<n;i++)
{
if(a[i]==x)
{
cout<<"Number "<<x<<" is present in position"<<i+1<<endl;
flag==1;
}
}
if(flag==0)
{
cout<<"Search is unsuccessful"<<endl;
}
system("PAUSE");
}
it looks good to me. It is one way to do it. The brace count wasn't correct but it looks like it would work.