Error with Exit Value 1

[dspartan]

Hello,

I have a general program that compiles but does not run properly. I have set flags in the program to pinpoint where the error is. Here is the function where the problem arises:

float* inputScores() // fills an array of the judges' scores via for loop
{
	//float scoreArray[7];
        float userInput; // input made by the user
	
	for(int incrementor = 0; incrementor < NUMBER_OF_JUDGES; incrementor++){ // loop that will continue for how many judges there are
		cout << "Please enter the score for Judge "
                     << incrementor + 1 << ".(0 - 10)\n";
		cin >> userInput; // receives user input
		scoreArray[incrementor] = userInput; // fills array with individual user inputs
                cout << scoreArray[incrementor];
        }
	
	return scoreArray;
}

I have made scoreArray and NUMBER_OF_JUDGES global variables.

The program builds with no errors. When the last input of the For loop is entered, the program stops and this error occurs:

RUN FAILED (exit value 1, total time: 6s)

I have tried increasing the size of the array so I make sure there is enough room, but to no avail. Also, I have put some random cout's to make sure the For loops or the function finishes and it seems the program just stops at line 9 during the last loop.

Thank you for reading.

[helios]

If scoreArray is an array local to inputScores, it's illegal to return pointers to local objects.

[dspartan]

I have changed scoreArray to be a global variable, hence why it is commented out.

Edit: Oh, I see the problem now, let me see if I can change it up a bit. Thanks for the insight.

[Computergeek01]

Declare "scoreArray" as static. This tells the compiler that the data needs to survive outside of the function.