Same Typely Funcs Definition

[Helegurbann]

#include <iostream>
#include <typeinfo>
using namespace std;
int add(){
    int a,b;
    a=25;
    b=35;
    return (a+b);
    }
   
   (typeid(add))transaction(){  }
    
    
    int main(){
      cout<<transaction()<<endl;
        system("pause");
        return 0;
        }

How can i definition "transaction()" func.

[helios]

How about

template <typename T>
struct foo{
    static T add(){ /*...*/ }
    static T transaction(){ /*...*/ }
};

//...

foo<int>::add();
foo<int>::transaction();

?

[hanst99]

or

auto transaction() -> decltype(add())
{
/* */
}

But really, go with what helios said.

[Helegurbann]

Yes thank u.hanst99's answer is my answer.

[hanst99]

Not really. helios version is better suited in most cases, my version is mostly for template functions where the result can't be easily determined, like this:

template<typename T1, typename T2>
auto add(T1 left, T2 right) -> decltype(left+right)
{
return left+right;
}

here left+right may either be T1, T2 or something completely different, that's why you need the decltype specification. But with the example you showed us, helios version is better.