related to function pointer

[somyamishra1985]

Hi I have just written a small code to understand function pointer.
bellow is the code in ms visual studio

#include "stdafx.h"
#include <iostream>
#include "conio.h"

using namespace std;

class Data
{
private:
int Ix;
public:
int setData(int Ivalue)
{
Ix=Ivalue;
return Ix;
}
};

int main()
{
Data MyData;
int (Data::*fnptr)(int)=&Data::setData;
int i=(MyData.*fnptr)(10);
cout<<i;
getche();
return 0;
}

plz help me to pass this function pointer to other function for some manipulation.
for Example
check(10,(MyData.*fnptr)(10))
for checking both values are same or not.

[hamsterman]

(MyData.*fnptr)(10) is not a function pointer. fnptr is. (MyData.*fnptr)(10) is just the value returned by the function fnptr points to.
Also, when you deal with function pointers, you should typedef them. It all becomes clear then.

[Syuf]

bool check(int i, int (MyData::*_mem_fun_ptr)(int) );

[1vRz3TCk]

#include <iostream>

using namespace std;

#define CALL_MEMBER_FN(object,ptrToMember)  ((object).*(ptrToMember))

class Data
{
private:
    int Ix;
public:
    int setData(int Ivalue)
    {
        Ix=Ivalue;
        return Ix;
    }
};

typedef int(Data::*data_fnptr)(int x); //Much easier if you typedef it

void userCode(data_fnptr p)
{ 
     //... 
}

int main()
{
    Data MyData;

    data_fnptr ptr = &Data::setData;

    int i= CALL_MEMBER_FN(MyData,ptr)(10);

    userCode(ptr);

    cout<<i;
    return 0;
}

P.S. It is a pointer-to-member-function