std::exception problem

[Null]

Hi, I'm writing an exception class but the compiler keeps complaining about it's destructor:

class myexception : public std::exception
{
public:
  std::string msg;
  virtual const char* what() const throw()
   {
       return "error blah blah";
   }
};


int main()
{
    // ...
}

error: looser throw specifier for 'virtual myexception::~myexception()'
c:\program files (x86)\mingw\bin\..\lib\gcc\mingw32\4.5.2\include\c++\exception|65|error: overriding 'virtual std::exception::~exception() throw ()'|

If I comment out std::string msg; it works fine

class myexception : public std::exception
{
public:
  //std::string msg;
  virtual const char* what() const throw()
   {
       return "error blah blah";
   }
};

How can I fix the error in the first example without commenting out std::strting msg?

Thanks for help.

[firedraco]

The compiler generated destructor does not include the "throw()" I believe, so try defining it like that yourself.

[ahura24]

its out of scope !!!!!!!!!!!! its too dangerous !!!!!!!!

you return address of variable that is dead !!!

char *what()
{
return "asdfasdf"; //// ITS DEAD VARIABLE
}

and if works correctly , your compiler is out of service !!

class myexception : public std::exception
{
public:
std::string msg;
virtual const char* what() const throw()
{
return msg.c_str();
}
};

compile correctly

[Null]

@ahura24: there's no problem since what() returns const char * and string literals in C++ are of type const char *.

@firedraco: you was right:

class myexception : public std::exception
{
public:
  std::string msg;
  virtual const char* what() const throw()
   {
       return "error blah blah";
   }
  ~myexception() throw()
  {

  }
};

Does this mean that the default constructor is not generated/called when there are no objects to destroy?