ASCII character table. Help needed.

[Brad1]

How would i get this program to print only ten characters per line?

#include <iostream>
using namespace std;

int main()
{
for (int i = 33; i < 127; i++)
{
std::cout << i << ": " << (char)i << std::endl;
}
return 0;
}

[Azagaros]

if you wanted to print ten characters a line

set up a counter variable, not a loop.

int count = 0;

increment the counter for each letter

count++;

remove the endl from your print line and put it in an if like

      if(count < 10)
      {
               // reset the count
               count = 0;
               // dump the endl;
               std::cout << std::endl;
      }

I will let you figure out the rest, but that is the basic logic.

[Turbine]

#include <iostream>
using namespace std;

int main()
{
   for (int i = 33; i < 127; i++)
   {
      std::cout << i << ": " << (char)i << std::endl;
      if ((i - 32) % 10 == 0)
         cout << endl;
   }
   return 0;
}

In my condition I'm saying, make the value start at 1, after each 10 characters add an new line.

[Brad1]

@Turbine

I ran your code and it put them in groups of ten but they still were all on the same line. I need to have 10 per line kinda like rows in a table

[Azagaros]

// the correction to his code is

#include <iostream>
using namespace std;

int main()
{
   for (int i = 33; i < 127; i++)
   {
      std::cout << i << ": " << (char)i;
      if ((i - 32) % 10 == 0)
         cout << endl;
   }
   return 0;
}

This might be what you are looking for.

[Brad1]

Thank you, thats what i was looking for do you know how i could use setw to make it look more spacious.

[buffbill]

#include<iomanip>
cout<<setw(4)<<//some var<<setw(4)<<//some other var<<//etc.