Ending a program within an "if" loop - break, exit(1), or something else?

[fertileneutrino]

hey,

i would like to write an "if" loop so that when the condition of the if loop is satisfied (so the statements in the if loop runs), the program quits.

i have tried exit(1); but this ends the CERN Root session in addition to ending the program. i know the use of break is not appropriate within an if loop (or so i've been told).

what would be the proper command to end the program?

[PanGalactic]

Can you explain what you mean by an "if loop"? "if" is not a looping construct. "for", "while" and "do/while" are looping constructs in C++.

Can you show us some code? That would help us give a cogent answer to your question.

[zb0S216C]

Loop:/goto is also a loop construct. The reserved word break is used in loops to break out of them when a condition is met.

_Wazzak

[LB]

Labels can be used to simulate loops but you cannot break out of labels...they don't wrap anything.

[GbX36Up4]

while(number1 == 0){
// code here
}

The downside is that the loop ends when it isn't 0, here is another solution:

while(number1 == 0){
return 0;
}

that way when the number equals 0, it will stop the program using return 0; You can also have it do other things inside that same loop.

[xephon]

agree with logart. Personally, if I'll use return.

you can use as return 0 or just return. same effect a little different for compiler.

[GbX36Up4]

Lol we both have 31 posts :D

[zb0S216C]

logart wrote:

while(number1 == 0){
return 0;
}

Hmmmm once return is encountered, the loop ends, along with the function. I don't see the point in placing a return statement there. A simple if statement would suffice. For example:

while( true )
{
    if( Number == 0 )
        // Break from the loop
        break;
}

_Wazzak

[PanGalactic]

@Framework: one doesn't discuss goto as a looping construct in polite company. ;-)

[GbX36Up4]

Mine uses only 3 lines and works just as fine?

[zb0S216C]

logart wrote:

Mine uses only 3 lines and works just as fine?

In your 2^nd loop example, your loop never lives past the first loop, therefore the loop becomes pointless. Your 1^st example however, is fine.

_Wazzak

[GbX36Up4]

I didn't mean for them to be used in the same code, just two different solutions for the same problem, not one solution.