dynamic array of strings problem
Oct 4, 2008 at 2:29pm UTC
Can anyone figure out why each of these are writing to the same address space. I can't use anything else but a dynamic array of strings. When I write B's to generationB it also writes B's to generationA as you can see if you run it.
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#include<iostream>
using namespace std;
int main()
{
int numRows=5;
int numColumns=5;
string* generationA;
string* generationB;
generationA = new string[numRows];
cout << "Generation A" << endl;
for (int i = 0; i < numRows; i++)
{
for (int j = 0; j < numColumns; j++)
{
generationA[i][j]='A' ;
cout << generationA[i][j];
}
cout << endl;
}
generationB = new string[numRows];
cout << "Generation B" << endl;
for (int i = 0; i < numRows; i++)
{
for (int j = 0; j < numColumns; j++)
{
generationB[i][j] = 'B' ;
cout << generationB[i][j];
}
cout << endl;
}
cout << "Generation A again:" << endl;
for (int i = 0; i < numRows; i++)
{
for (int j = 0; j < numColumns; j++)
{
cout << generationA[i][j];
}
cout << endl;
}
cout << "Generation A is pointing at " << generationA <<endl
<< "Generation B is pointing at " << generationB <<endl;
delete []generationA;
delete []generationB;
system("pause" );
}
Last edited on Oct 4, 2008 at 2:30pm UTC
Oct 4, 2008 at 9:36pm UTC
You are not using strings correctly.
generationA = new string[numRows];
creates an array of strings, each of which is length 0.
Then your for() loop does this:
This accesses the jth element of each string. But each string is length 0, so the jth element does not technically exist.
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