warning: taking address of temporary

[chameleon]

Ok, I understand what is going wrong.
But how wrong is wrong?
Can I use it?

int func(const class MyClass *a) { return a->int_member; }

int main() {
   func(&MyClass());
   return 0;
}

[Zhuge]

It's a warning because you could use that address outside of the scope of the temporary and have an invalid pointer.

[zb0S216C]

Why are you calling MyClass's constructor as an argument? This doesn't make any sense to me.

_Wazzak

[LB]

He's instantiating a class object on-the-fly, Framework, just for testing purposes.

[chameleon]

Ok, so I can use it in my code without problems on different compilers.

[guestgulkan]

He can avoid the warning by using a reference rather than pointer:

int func(  const MyClass & a) { return a.int_member; }

int main()
{
    func(MyClass());

    return 0;
}

[Athar]

Ok, so I can use it in my code without problems on different compilers.

No, that's not valid C++. Use a reference, as mentioned.