copy one array into another

[smelas]

Hi,

an array like this;

int numbers[10] = {31,28,31,2,31,10,31,31,9,31,3,31};

and I would like to pair the elements of the array like the following (I mean, I would like to sum each two element);

0+1, 1+2, 2+3,....,7+8, 8+9 and would like to copy the new values into another array which will be int numbers[9].


I found something like that;

void reverseWord(char word [], char reverse [], int howMany)
{
     for (int i = 0; i < howMany; i++)
        reverse[ howMany - i ] = word[ i ];

     return;
}

but how can I sum the two elements accordingly.. ? If I write with if conditions, it looks long and not efficient. Is there any other easier way ?

[Browni3141]

0+1, 1+2, 2+3,....,7+8, 8+9 and would like to copy the new values into another array which will be int numbers[9].

Do you mean: 31+28, 28+31, 31+2,...3+31, and copy those new values to a different array?

If yes then a simple for loop should suffice.

[smelas]

that's right. 31+28, 28+31, 31+2,...3+31, and copy those new values to a different array.

[Browni3141]

In pseudoish-code:

for (int i = 0; i < size_of_array-1; i++)// size_of_array-1 so that i+1 is not out of bounds.
    new_array[i] = sum of array[i] and array[i+1];

Try that out.

[PanGalactic]

C++ STL algorithms will do that for you:

#include <algorithm>
#include <functional>
...
    int numbers[12] = {31,28,31,2,31,10,31,31,9,31,3,31};
    int result[11];
    std::transform(numbers, numbers + 11, numbers + 1, result, std::plus<int>());

This just passes "numbers" as two ranges offset by 1, sums them, and stores the result in "result".

[smelas]

This is also good to know. thanks to both of you,, below one works.

#include <iostream>

using namespace std;

int main () {
        int array[6] = {2, 6, 6, 5, 3, 7};
        int newArray[5] = {0, 0, 0, 0, 0};

        for (int i = 0; i < 5; i++) {// minus one so that i+1 is not out of bounds.
            newArray[i] = array[i] + array[i+1];
            cout << newArray[i] << endl;
        }
}