Cin being Ignored in loop.

[abakiz]

Basically this is a small part in a big program I've developed, I've managed to create an entire game of monopoly, now I've only got one error left... and it's really silly one too.

When I input the number of players as anything else but a number, the loop is being ignored and continually outputs the same line.

int players = 0;

cout << "Welcome to Monopoly" << endl;
	cout << "How many players do you want? (2 - 6)" << endl;
	cin >> players;

	//checking if players are between 2 and 6
	while(players > 6 || players < 2)
	{
		cout << "players must be between 2 n 6" << endl;
		cin >> players;
	}

I've tried cin.ignore, I've tried cout << flush, I've tried converting it to a string and float, then back too and int, I've tried resetting the int within the loop...

Nothing works.

So any help would be much appreciated. Thanks Olly

[abakiz]

Ok I found a solution, I have to use

cin.clear();
cin.ignore(1000, '\n');

Got too use both of them because if you only use ignore it ignores the symbols but if you use clear it also ignores the characters.

[satyamkrishna2004]

u can get input in form of a string. get it checked whether it contains only digit.
then stream it into players


#include<sstream>
#include<string>
main()
{
string play;
int players;
getline(cin,play);
{
check if string contains all digit
}

stringstream(play) >> players;