messing with hex

[Onceler]

I am trying to write a program that will read in four bytes in hex and see if it is <= 07070707(hex)
I am stumped about how to do this
do I have to write it as 0x07 0x07 0x07 0x07?
also would I have to write it back that way if I wrote to a file or could I just write 07070707?
Thanks

[wolfgang]

Put 0x in front of the number. 0x07070707.

[Onceler]

would it still be four bytes with the 0x added on or not?
thanks

[zwA4jE8b]

you could test it with the sizeof() function probably

[Athar]

0x just indicates that the digits following are hexadecimal ones, it has no effect on how the number is stored.
You can write 0x07070707, 117901063 (decimal) or 0701603407 (octal) - all three specify the same number.

[wolfgang]

Here, if you want to see if it will fit in your integer or 4 byte number here's a test program:

#include <iostream>
#include <limits>

int main ()
{
	int MAX = std::numeric_limits<int>::max();
	std::cout << "The maximum size of an integer on this machine is " << sizeof(int) << " and the maximum value it can hold is " << MAX << std::endl;
	if ( MAX >= 0x07070707 || 0x07070707 < 0 )
		std::cout << "The hex number 0x07070707 which is " << long(0x07070707) << " in decimal is smaller than an integer on this machine." << std::endl;
	else
		std::cout << "The hex number 0x07070707 which is " << long(0x07070707) << " does not fit into an integer on this machine.";

	return 0;
}