Calculating grade averages

[jason007thomas]

I'm trying to get this program to calculate the grade average of 25 kids but now I just got stuck with the calculating the average part

what did I do wrong here

#include <iostream>
#include <string>

using namespace std;

int main()
{
	//step 1: Declare variables
	string firstname = " ";
	float avg=0, grade1=0, grade2=0, grade3=0;
	char finalGrade = 'F';
	int studentCount=0;
	double Average = (grade1+grade2+grade3)/3;
	int 90-100=A, 80-89.9=B, 70-79.9=C, 60-69.9=D, 0-59.9=F; 

	//step 2: Design the loop to process students
	for(int studentCount=1; studentCount<=25; studentCount=studentCount+1)
	{
	  
		//step 3a: Get the input
		cout<<"Please Enter Grade #1"<<endl;
		cin >> grade1 ;
		cout<<"Please Enter Grade #2"<<endl;
		cin >> grade2 ;
		cout<<"Please Enter Grade #3"<<endl;
		cin>> grade3 ;
		//step 3b: Calculate the average
		cout<<Average<<endl; 
		 

		//step 3c: Determine the letter grade

		//step 3d: Write the output
	}

	return 0;
}

I Know its something small
Thanks fellas!!! and know this isn't my HW.

[zb0S216C]

First, grade1, grade2, grade3 are of type float, where, Average is of type double. This should not affect the code in a large way, however. Second, Average is computed before the user enters the grades. Calculate the grades after the user has entered the grades. Third, it's easier to write studentCount++ instead of studentCount=studentCount+1 in the for loop.

EDIT: int 90-100=A, 80-89.9=B, 70-79.9=C, 60-69.9=D, 0-59.9=F; is not valid. You cannot have identifiers beginning with numbers and you also cannot have identifiers which are computations. Instead, do this: int A( 90-100 ), B( 80-89.9 ), C( 70-79.9 ), D( 60-69.9 ), F( 0-59.9 );

Note: Any floating points that are assigned to a variable, which is of type int, are truncated.