How do I get it to show the equation on the output?

[MiscSong]

#include<iostream>
  using namespace std;

int main()
{
//Declare variable
    int n1; int n2; int n3; int n4; int sum; int prod;
    
//Get user input
    cout<<"Enter 4 #'s";
    cout<<endl;
    cin>>n1; cin>>n2; cin>>n3; cin>>n4;
    cout<<endl;

//Perform calculations
    //square each #
        n1*n1;
        n2*n2;
        n3*n3;
        n4*n4;
        n2-n4;
        n3*(n1+n2+n4);
        (n2*n3)-(n1+n4);
//Display result
    //Each # squared
        cout<<n1*n1<<endl;
        cout<<n2*n2<<endl;
        cout<<n3*n3<<endl;
        cout<<n4*n4<<endl;
        cout<<n2-n4<<endl;
        cout<<n3*(n1+n2+n4)<<endl;
        cout<<(n2*n3)-(n1+n4)<<endl;  

    return 0;
}

so far i've got the program itself to work the only thing i can't seem to get is how to show the actual equation in the output.

for example if i entered 3 7 4 2 the output would be:

3^2=9
7^2=49
4^2=16
2^2=4
7-2=5
4(3+7+2)=4X12=48
(7X4)-(3+2)=28-5=23

[hamsterman]

int n1; int n2; int n3; int n4; int sum; int prod;
You don't have to repeat 'int'. int n1, n2, n3, n4, sum, prod;

cin>>n1; cin>>n2; cin>>n3; cin>>n4;
Operator >> returns istream& so you can write cin >> n1 >> n2 >> n3 >> n4;

        n1*n1;
        n2*n2;
        n3*n3;
        n4*n4;
        n2-n4;
        n3*(n1+n2+n4);
        (n2*n3)-(n1+n4);

This code doesn't do anything. You calculate a square but you don't assign it to anything. A working example could be int n1square = n1*n1;

As for the original problem, you can only write it yourself: cout << n1 << "^2 = " << n1*n1 << endl;

[MiscSong]

okay so far i've got

#include<iostream>
  using namespace std;

int main()
{
//Declare variable
    int n1, n2, n3, n4, prod, sum;
    
//Get user input
    cout<<"Enter 4 #'s";
    cout<<endl;
    cin>>n1>>n2>>n3>>n4;
    cout<<endl;

//Perform calculations
    //square each #
        int n1square = n1*n1;
        int n2square = n2*n2;
        int n3square = n3*n3;
        int n4square = n4*n4;
        n2-n4;
        n3*(n1+n2+n4);
        (n2*n3)-(n1+n4);
//Display result
    //Each # squared
        cout<<n1<<"^2="<<n1*n1<<endl;
        cout<<n2<<"^2="<<n2*n2<<endl;
        cout<<n3<<"^2="<<n3*n3<<endl;
        cout<<n4<<"^2="<<n4*n4<<endl;
        cout<<n2-n4<<endl;
        cout<<n3*(n1+n2+n4)<<endl;
        cout<<(n2*n3)-(n1+n4)<<endl;

    return 0;
}

now how do i assign the bold lines to show on the output?

[hamsterman]

Mate, you're missing the point.
int n1square = n1*n1; this line takes value of n1, multiplies it with itself and puts the result in n1square. It doesn't do anything else. You never use n1square in your code. Why is it here? You could have used it on line 26, but really you don't have to.

As for printing, equation will not print itself. If you want that to see them, you have to print them. example:

int a = 1, b = 4, c = 3;
cout << a << "*x^2 + " << b << "*x + " << c << " = " 
<< a << "*(x + " << (b+sqrtf(b*b-4*a*c))/2/a << ")*(x + "
<< (b-sqrtf(b*b-4*a*c))/2/a << ")";

Gives

1*x^2 + 4*x + 3 = 1*(x + 3)*(x + 1)