Trying to print adresses of 2D dynamic arrays

[gustafssonsami]

I've created a program that is able to create a staggered 2D dynamic array.
I pass this array to function and try to cout it's "childrens" memory locations in two ways:

cout << arr[i] << " : ";
cout << &arr[i] << " : ";

Both of these return different memory locations.
For example:

0x556ec382dbf0 : 0x556ec382d2c8 : 
0x556ec382dc30 : 0x556ec382d2d0 :
0x556ec382dc50 : 0x556ec382d2d8 :

I know that & is address operator and it should return the address of the variable, but I still don't understand the difference between what these two print.

Here's the full code:

int main(){
    int size, temp, temp2;

    cin >> size;

    int **arr = new int*[size];
    int *sizes = new int[size];

    for(int i = 0; i < size; i++){
        cin >> temp;    

        arr[i] = new int[temp];
        sizes[i] = temp;
    }
    
    while(true){
        print2DSArray(arr, sizes, size);

        cout << "Which row change? : ";
        cin >> temp;
        cout << "To what lenght? : ";
        cin >> temp2;

        change2DSArrayRowL(arr, sizes, size, temp, temp2);
    }
}


void print2DSArray(int **arr, int *sizes, int size){
    for(int i = 0; i < size; i++){
        cout << arr[i] << " : ";
        cout << &arr[i] << " : ";
        for(int j = 0; j < sizes[i]; j++){
            cout << arr[i][j] << " ";
        }
        cout << endl;
    }
}

[MikeyBoy]

arr[i] is the value stored in the i'th element of arr. That means it is the address of the memory allocated at line 12.

&arr[i] is the memory address of the i'th element of arr. That means it will be one of the addresses in the range of memory allocated at line 6.