Default values in parameters

[LB]

Why is it not valid syntax to do something like this? It's not important, it's just that it would seem it is valid.

void MyFunction(int a, int b = 2, int c, int d){/*blah*/}

Then call it like this
MyFunction(1, , 3, 4);
?

It gives an error that in the function definition, c and d are missing their default parameters. I was under the understanding that default parameters didn't have to be the last ones! The wording in the tutorial is what confused me:

This value will be used if the corresponding argument is left blank when calling to the function.

This gave me the impressing that I could simply skip passing a parameter and it would use the default value.

Like I said, I am simply curious. It's not important, I can just make my function parameters out of order (or add a default value for all of them :S )

[Kyon]

No, the way you're doing it, you are literally sending a value (void). When you define default values, you always define with the last one being your starting point:

void MyFunction(int a, int b = 2, int c = 3, int d = 4){/*bla*/} // legit way to use default values

MyFunction(3); // MyFunction(3, 2, 3, 4);
MyFunction(3,8); // My Function(3, 8, 3, 4);
// and so on 

It's also possible to define a default for all the parameters, in that case you would write just MyFunction(). Do NEVER forget the parenthesis!

[LB]

You answered a question I didn't ask, but you answered my original question at the same time anyway. Thanks, I can see how it would cause problems now. :)