Number Frequency

[1Cj3ko23]

Allow the user to enter values between 1-9, up to 2 billion values. When the user enters a 0 report the frequency of each digit and terminates the program.

The following is a sample run.

Welcome to Brent's frequency analyzer.  Enter some numbers between 1-9, 
more than none, and less than 2,000,000,000.  Enter a 0 to get the results.
Number: 5
Number: 8
Number: 5
Number: 3
Number: 7
Number: 5
Number: 0
Number Frequencies
   Number:  1  2  3  4  5  6  7  8  9  
Frequency:  0  0  1  0  3  0  1  1  1

This is what I have so far.

#include <bits/stdc++.h>
using namespace std;


int main(){
	int n = 1;
	int counter = 0;
	int intArray[100];
	int freqArray[10];
	
	cout << "Welcome to Kolton's frequency analyzer. Enter some numbers between 1-9,";
	cout << " more than none, and less than 2,000,000,000. Enter a 0 to get the results." << endl;
	
	while(n!=0){
		cout << "Enter a number: ";
		cin >> n;
		if (n!=0){
			intArray[counter] = n;
			counter++;
		}
	}
	
	for(int i = 0; i < counter; i++){
		cout << intArray[i] << endl;
	}
		
	cout << "You entered " << counter << " numbers.\n";
	cout << "The middle number entered is: " << intArray[counter/2] << " at index " << counter/2 << endl;
	
	return 0;
}

[dutch]

You don't need to store the input numbers. If you did need to store them you would need space for two billion of them! I just typed the following in here so it's untested (and incomplete).

#include <iostream>
using namespace std;

int main() {
    int freq[10] { }; // the braces initialize the array elements to 0

    cout << "Enter up to two billion numbers from 1 to 9. Enter 0 to stop.\n";

    while (true) {
        int n;
        cin >> n;
        if (n == 0) break;
        if (n > 0 && n < 10)
            ++freq[n];
        else
            cout << "Numbers must be from 1 to 9\n";
    }

    for (int i = 1; i < 10; ++i)
        cout << freq[i] << ' ';
    cout << '\n';
}

Don't use bits/stdc++.h. It's nonstandard and generally for retards only. Instead, include the actual C++ headers that you use.

[seeplus]

#include <iostream>

int main() {
	int freq[10] { };

	std::cout << "Enter number(s) from 1 to 9. Enter 0 to stop.\n";

	for (int n {}; (std::cin >> n) && (n != 0); )
		if (n > 0 && n < 10)
			++freq[n];
		else
			std::cout << "Numbers must be from 1 to 9\n";

	for (size_t f = 1; f < 10; ++f)
		std::cout << f << ' ' << freq[f] << '\n';
}