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Variable Including and int and char

jzone3 (26)
I currently made a variable using
string dim;
This does not include both at once because I am trying to make it as 3-D or 2-D for a Volume calc but I can use a number and letter.
Disch (13742)
what?

Can you explain your problem a little better?
jzone3 (26)
I want to create a variable that wen u use cin >>
it will store "3d" or "2d"
filipe (1165)
A std::string is a container that can hold chars. You can store "3d" in a string, but both '3' and 'd' will be stored as chars. If you want to keep the integer part for calculations, it would be better to store it as an int.
R0mai (730)
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struct dim {
    char ch;
    int i;
};
std::istream& operator>>(std::istream& is, dim& d) {
    /*Implement this to read from 'is' to 'd'*/ 
   return is;
}
Last edited on
jzone3 (26)
filipe I tried using a string but it does not work

romal were do I insert that?
this is my code so far
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#include <iostream>
#include <math.h>
#include <string>
using namespace std;

int main() 
{
	double cube_a;
	cout << endl;
	cout << "Welcome To The Volume Calculator" << endl;
	sleep(1);
	cout << "Here are some variables you will be working with:" << endl;
	cout << endl;
	sleep(1);
	cout << "h = height" << endl;
	cout << "(vertical)" << endl;
	sleep(1);
	cout << "r = radius" << endl;
	cout << "(half the diameter of a circle)" << endl;
	cout << endl;
	sleep(1);
	string dim;
	while (dim != "3-D" && dim != "2-D" && dim != "3d" && dim != "2d" && dim != "3D" && dim != "2D" && dim != "3-d" && dim != "2-d") {
		cout << "Would You Like To Use 3-D or 2-D Shapes?" << endl;
		cin >> dim;
		
		if (dim == "3-D" || dim == "2-D" || dim == "3d" || dim == "2d" || dim == "3D" || dim == "2D" || dim == "3-d" || dim == "2-d")
		{}
		
		else {
			cout << "Please Try Again" << endl;
		}
	if (dim == "3-D" || dim == "3D" || dim == "3d" || dim == "3-d") {
		
		string shape;
		while (shape != "Cube" && shape != "cube" && shape == "cylinder" && shape == "Cylinder") {
			cout << "Please Choose The Shape That You Would Like To Find The Volume Of" << endl;
			cin >> shape;
			if (shape == "Cube" || shape == "cube") {
				cout << endl;
				cout << "The formula for the volume of a cube is:" << endl;
				cout << "V=a³" << endl;
				sleep(1);
				cout << "Enter a:" << endl;
				cin >> cube_a;
				cout << endl;
				cout << "V=" << pow(cube_a, 3) << endl;
				sleep(5);
			}
			if (shape == "cylinder" || shape == "Cylinder") {
				cout << endl;
				cout << "The formula for the volume of a cylinder is:" << endl;
				cout << "V=πr²h" << endl;
				sleep(1);
				cout << "Enter h:" << endl;
				
			}
			else {
			}

		}
	}
	if (dim == "2d" || dim == "2D" || dim == "2-D" || dim == "2-d") {
		cout << " " << endl;
	}
	else{
	}
}
	

}
Phantom139 (41)
for std::string 's you should be using:

string.compare(string2);

if the return value is 0, the two strings match, or in this case:

if(dim.compare("3d") == 0) {
do stuff
}

and so on.

I hope this helps.
firedraco (6243)
for std::string 's you should be using:

string.compare(string2);


Operator == is a lot faster and more obvious IMO.
jzone3 (26)
do I put
string.compare(string2);
after I create a string or replace
string dim;
??
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